If the ellipse \( \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 \) meets the line \( \dfrac{x}{7}+\dfrac{y}{2\sqrt{6}}=1 \) on the x-axis and the line \( \dfrac{x}{7}-\dfrac{y}{2\sqrt{6}}=1 \) on the y-axis, then the eccentricity of the ellipse is:
\( \dfrac{5}{7} \)
\( \dfrac{2\sqrt{6}}{7} \)
\( \dfrac{3}{7} \)
\( \dfrac{2\sqrt{5}}{7} \)
