Let a triangle \( ABC \) be inscribed in the circle \( x^{2}-\sqrt{2}(x+y)+y^{2}=0 \) such that \( \angle BAC=\frac{\pi}{2} \). If the length of side \( AB \) is \( \sqrt{2} \), then the area of the \( \triangle ABC \) is equal to:
3
1
2
0