Let the abscissae of the two points \( P \) and \( Q \) be the roots of \( 2x^{2} - r x + p = 0 \) and the ordinates of \( P \) and \( Q \) be the roots of \( x^{2} - s x - q = 0 \). If the equation of the circle described on \( PQ \) as diameter is \( 2(x^{2} + y^{2}) - 11x - 14y - 22 = 0 \), then \( 2r + s - 2q + p \) is equal to ______.
