Solution:
Group \( A \Rightarrow 4 \) men & \( 5 \) women
Group \( B \Rightarrow 5 \) men & \( 4 \) women
Selection of \( 4 \) person from each group, as well as \( 4 \) men & \( 4 \) women should be in selection.

Group A	Group B	No of way to select
\( 0\text{M}, 4\text{W} \)	\( 4\text{M}, 0\text{W} \)	\( {}^{4}C_{0} \times {}^{5}C_{4} \times {}^{5}C_{4} \times {}^{4}C_{0} = 1 \times 5 \times 5 \times 1 = 25 \)
\( 1\text{M}, 3\text{W} \)	\( 3\text{M}, 1\text{W} \)	\( {}^{4}C_{1} \times {}^{5}C_{3} \times {}^{5}C_{3} \times {}^{4}C_{1} = 4 \times 10 \times 10 \times 4 = 1600 \)
\( 2\text{M}, 2\text{W} \)	\( 2\text{M}, 2\text{W} \)	\( {}^{4}C_{2} \times {}^{5}C_{2} \times {}^{5}C_{2} \times {}^{4}C_{2} = 6 \times 10 \times 10 \times 6 = 3600 \)
\( 3\text{M}, 1\text{W} \)	\( 1\text{M}, 3\text{W} \)	\( {}^{4}C_{3} \times {}^{5}C_{1} \times {}^{5}C_{1} \times {}^{4}C_{3} = 4 \times 5 \times 5 \times 4 = 400 \)
\( 4\text{M}, 0\text{W} \)	\( 0\text{M}, 4\text{W} \)	\( {}^{4}C_{4} \times {}^{5}C_{0} \times {}^{5}C_{0} \times {}^{4}C_{4} = 1 \times 1 \times 1 \times 1 = 1 \)

Hence total selection \( = 5626 \)

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