Let \( 0 \le r \le n \). If \( \ ^{n+1}C_{r+1} : \ ^{n}C_{r} : \ ^{n-1}C_{r-1} = 55 : 35 : 21 \), then \( 2n + 5r \) is equal to:
\( 55 \)
\( 62 \)
\( 60 \)
\( 50 \)