Let the image of the point \( P(2,-1,3) \) in the plane \( x+2y-z=0 \) be \( Q \). Then the distance of the plane \( 3x+2y+z+29=0 \) from the point \( Q \) is :
\( \dfrac{24\sqrt{2}}{7} \)
\( 3\sqrt{14} \)
\( 2\sqrt{14} \)
\( \dfrac{22\sqrt{2}}{7} \)