A Carnot engine with efficiency \( 50\% \) takes heat from a source at \( 600 \, \text{K} \). In order to increase the efficiency to \( 70\% \), keeping the temperature of sink same, the new temperature of the source will be:
\( 300 \, \text{K} \)
\( 1000 \, \text{K} \)
\( 900 \, \text{K} \)
\( 360 \, \text{K} \)