The surface tension of a soap bubble is \( 0.03 \, \text{N}/\text{m} \). The work done in increasing the diameter of bubble from \( 2 \, \text{cm} \) to \( 6 \, \text{cm} \) is \( \alpha \pi \times 10^{-4} \, \text{J} \). The value of \( \alpha \) is _________. (Take \( \pi = 3.14 \))