A circular disc has radius \( R_1 \) and thickness \( T_1 \). Another circular disc made of the same material has radius \( R_2 \), and thickness \( T_2 \). If the moment of inertia of both discs are same and \( \frac{R_1}{R_2} = 2 \) then \( \frac{T_1}{T_2} = \frac{1}{\alpha} \). The value of \( \alpha \) is __________.