If the solution \( y=y(x) \) of the differential equation \( (x^4+2x^3+3x^2+2x+2)\,dy-(2x^2+2x+3)\,dx=0 \) satisfies \( y(-1)=-\dfrac{\pi}{4} \), then \( y(0) \) is equal to:
\( -\dfrac{\pi}{12} \)
\( \dfrac{\pi}{2} \)
\( 0 \)
\( \dfrac{\pi}{4} \)