The line, that is coplanar to the line \( \dfrac{x+3}{-3}=\dfrac{y-1}{1}=\dfrac{z-5}{5} \), is:
\( \dfrac{x+1}{1}=\dfrac{y-2}{2}=\dfrac{z-5}{5} \)
\( \dfrac{x-1}{-1}=\dfrac{y-2}{2}=\dfrac{z-5}{5} \)
\( \dfrac{x+1}{-1}=\dfrac{y-2}{2}=\dfrac{z-5}{4} \)
\( \dfrac{x+1}{-1}=\dfrac{y-2}{2}=\dfrac{z-5}{5} \)