Let \( A \) be the point of intersection of the lines \( L_1 : \, \frac{x-7}{1} = \frac{y-5}{0} = \frac{z-3}{-1} \) and \( L_2 : \, \frac{x-1}{3} = \frac{y+3}{4} = \frac{z+7}{5} \).Let \( B \) and \( C \) be the points on the lines \( L_1 \) and \( L_2 \) respectively such that \( AB = AC = \sqrt{15} \). Then the square of the area of the triangle \( ABC \) is:
