If the solution curve of the differential equation \( (2x-10y^{3})\,dy+y\,dx=0 \), passes through the points \( (0,1) \) and \( (2,\beta) \), then \( \beta \) is a root of the equation:
\( 2y^{5}-y^{2}-2=0 \)
\( y^{5}-y^{2}-1=0 \)
\( y^{5}-2y-2=0 \)
\( 2y^{5}-2y-1=0 \)