If the sum and the product of mean and variance of a binomial distribution are \( 24 \) and \( 128 \) respectively, then the probability of one or two successes is:
\( \dfrac{33}{2^{32}} \)
\( \dfrac{33}{3^{29}} \)
\( \dfrac{33}{2^{28}} \)
\( \dfrac{33}{2^{27}} \)