A block of mass \( M \) slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is \( \theta \). The magnitude of the contact force will be:
\( Mg \)
\( Mg \cos \theta \)
\( \sqrt{Mg \sin \theta + Mg \cos \theta} \)
\( Mg \sin \theta \sqrt{1+\mu} \)