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Let \( y = y(x) \) be the solution curve of the differential equation \( x\left(x^{2}+e^{x}\right) \, dy + \left(e^{x}(x-2)y - x^{3}\right) dx = 0 , \, x > 0 \), passing through the point \( (1,0) \). Then \( y(2) \) is equal to:

Among the statements

(\( \mathrm{S1} \)) : The set \( \left\{ z \in \mathbb{C} - \{-i\} : |z| = 1 \text{ and } \frac{z-i}{z+i} \text{ is purely real} \right\} \) contains exactly two elements, and

(\( \mathrm{S2} \)) : The set \( \left\{ z \in \mathbb{C} - \{-1\} : |z| = 1 \text{ and } \frac{z-1}{z+1} \text{ is purely imaginary} \right\} \) contains infinitely many elements.

From a group of \( 7 \) batsmen and \( 6 \) bowlers, \( 10 \) players are to be chosen for a team, which should include atleast \( 4 \) batsmen and atleast \( 4 \) bowlers. One batsmen and one bowler who are captain and vice-captain respectively of the team should be included. Then the total number of ways such a selection can be made, is:

Let \( C_{1} \) be the circle in the third quadrant of radius \( 3 \), that touches both coordinate axes. Let \( C_{2} \) be the circle with centre \( (1,3) \) that touches \( C_{1} \) externally at the point \( (\alpha,\beta) \). If \( (\beta - \alpha)^{2} = \frac{m}{n} \), \( \gcd(m,n)=1 \), then \( m+n \) is equal to:

Let \( P \) be the parabola, whose focus is \( (-2,1) \) and directrix is \( 2x + y + 2 = 0 \). Then the sum of the ordinates of the points on \( P \), whose abscissa is \( -2 \), is:

Let \( A \) be a \( 3 \times 3 \) matrix such that \( \left| \operatorname{adj} \left(\operatorname{adj}(\operatorname{adj} A)\right) \right| = 81 \). If \( S = \left\{ n \in {Z} : \left(\left| \operatorname{adj}(\operatorname{adj} A) \right|\right)^{\frac{(n-1)^{2}}{2}} = |A|^{\left(3n^{2} - 5n - 4\right)} \right\} \), then \( \displaystyle \sum_{n \in S} |A|^{\left(n^{2} + n\right)} \) is equal to:

Let the system of equations:
\( 2x + 3y + 5z = 9 \),
\( 7x + 3y - 2z = 8 \),
\( 12x + 3y - (4 + \lambda)z = 16 - \mu \),
have infinitely many solutions. Then the radius of the circle centred at \( (\lambda, \mu) \) and touching the line \( 4x = 3y \) is:

Let \( x = -1 \) and \( x = 2 \) be the critical points of the function \( f(x) = x^3 + ax^2 + b \log_e |x|+1, \, x \neq 0 \). Let \( m \) and \( M \) respectively be the absolute minimum and the absolute maximum values of \( f \) in the interval \( \left[-2, -\frac{1}{2}\right] \). Then \( |M + m| \) is equal to: \( \text{(Take } \log_e 2 = 0.7 \text{)} \)

Let \( \triangle ABC \) be the triangle such that the equations of lines \( AB \) and \( AC \) be \( 3y - x = 2 \) and \( x + y = 2 \), respectively, and the points \( B \) and \( C \) lie on \( x \)-axis. If \( P \) is the orthocentre of the triangle \( ABC \), then the area of the triangle \( PBC \) is equal to:

If for \( \theta \in \left[ -\dfrac{\pi}{3}, 0 \right] \), the points \( (x, y) = \left( 3 \tan \left( \theta + \dfrac{\pi}{3} \right), \, 2 \tan \left( \theta + \dfrac{\pi}{6} \right) \right) \) lie on \( xy + \alpha x + \beta y + \gamma = 0 \), then \( \alpha^2 + \beta^2 + \gamma^2 \) is equal to:

Let the line \( L \) pass through \( (1, 1, 1) \) and intersect the lines \( \dfrac{x-1}{2} = \dfrac{y+1}{3} = \dfrac{z-1}{4} \) and \( \dfrac{x-3}{1} = \dfrac{y-4}{2} = \dfrac{z}{1} \). Then, which of the following points lies on the line \( L \)?

Let \( x_1, x_2, x_3, x_4 \) be in a geometric progression, If \( 2, 7, 9, 5 \) are subtracted respectively from \( x_1, x_2, x_3, x_4 \), then the resulting numbers are in an arithmetic progression. Then the value of \( \dfrac{1}{24} (x_1 x_2 x_3 x_4) \) is:

If the shortest distance between the lines $\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4}$ and $\frac{x}{1} = \frac{y}{\alpha} = \frac{z-5}{1}$ is $\frac{5}{\sqrt{6}}$, then the sum of all possible values of $\alpha$ is:

Let the angle $\theta, 0 < \theta < \frac{\pi}{2}$ between two unit vectors $\hat{a}$ and $\hat{b}$ be $\sin^{-1}\left(\frac{\sqrt{65}}{9}\right)$. If the vector $\vec{c} = 3\hat{a} + 6\hat{b} + 9\left(\hat{a} \times \hat{b}\right)$, then the value of $9(\vec{c}.\hat{a}) - 3(\vec{c}.\hat{b})$ is:

If the area of the region bounded by the curves \( y = 4 - \frac{x^2}{4} \) and \( y = \frac{x - 4}{2} \) is equal to \( \alpha \), then \( 6\alpha \) equals:

Let the set of all values of $p \in \mathbb{R}$, for which both the roots of the equation $x^2 - (p + 2)x + (2p + 9) = 0$ are negative real numbers, be the interval $(\alpha, \beta]$. Then $\beta - 2\alpha$ is equal to:

The integral $\int\limits_{0}^{\pi} \frac{(x + 3) \sin x}{1 + 3\cos^2 x} dx$ is equal to:

The remainder when $\left((64)^{(64)}\right)^{(64)}$ is divided by 7 is equal to:

The mean and standard deviation of \( 100 \) observations are \( 40 \) and \( 5.1 \), respectively. By mistake one observation is taken as \( 50 \) instead of \( 40 \). If the correct mean and the correct standard deviation are \( \mu \) and \( \sigma \) respectively, then \( 10(\mu + \sigma) \) is equal to:

is equal to:

$\text{The number of points of discontinuity of the function } f(x) = \left[ \frac{x^2}{2} \right] - [\sqrt{x}], x \in, \text{[0,4] where}$$[.] \text{ denotes the greatest integer function, is __________ .}$

For \( n \ge 2 \), let \( S_{n} \) denote the set of all subsets of \( \{1,2,\ldots,n\} \) with no two consecutive numbers. For example \( \{1,3,5\} \in S_{6} \) but \( \{1,2,4\} \notin S_{6} \). Then \( n\!\left(S_{5}\right) \) is equal to ____________.

The number of singular matrices of order \( 2 \), whose elements are from the set \( \{2,3,6,9\} \), is ____________.

$\text{Consider the hyperbola } \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \text{ having one of its focus at } P(-3,0). \text{ If the latus}$ $\text{rectum through its other focus subtends a right angle at } P \text{ and } a^2b^2 = \alpha\sqrt{2} - \beta, \alpha, \beta \in \mathbb{N},$ $\text{then } \alpha + \beta \text{ is ____________ .}$

The number of relations on the set \( A = \{1,2,3\} \), containing at most \( 6 \) elements including \( (1,2) \), which are reflexive and transitive but not symmetric, is ________________.

JEE MAIN 2025 7th April Morning Shift

Mathematics Physics Chemistry

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The remainder when $\left((64)^{(64)}\right)^{(64)}$ is divided by 7 is equal to: