If the points with position vectors \( \alpha \hat{i}+10\hat{j}+13\hat{k},\; 6\hat{i}+11\hat{j}+11\hat{k},\; \dfrac{9}{2}\hat{i}+\beta \hat{j}-8\hat{k} \) are collinear, then \( (19\alpha-6\beta)^2 \) is equal to:
\( 49 \)
\( 25 \)
\( 36 \)
\( 16 \)