Let the foot of perpendicular from the point \( (\lambda,2,3) \) on the line \( \dfrac{x-4}{1}=\dfrac{y-9}{2}=\dfrac{z-5}{1} \) be the point \( (1,\mu,2) \). Then the distance between the lines \( \dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z+4}{6} \) and \( \dfrac{x-\lambda}{2}=\dfrac{y-\mu}{3}=\dfrac{z+5}{6} \) is equal to:
