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JEE Advance | PYQ

If both the prisms are at minimum deviation condition, then \( \frac{n_2}{n_1} = \frac{\sin\!\left(\frac{A_1}{2}\right)}{\sin\!\left(\frac{A_2}{2}\right)} \)

If prism \( 2 \) is at minimum deviation condition, then \( \sin i_1 = n_2 \sin\!\left(\frac{A_2}{2}\right) \) is always true.

If both the prisms \( 1 \) and \( 2 \) are thin and are at minimum deviation condition with angles of deviation \( \delta_{m1} \) and \( \delta_{m2} \), respectively, then \( \theta = \frac{\delta_{m1}}{2\,(n_1 - 1)} + \frac{\delta_{m2}}{2\,(n_2 - 1)} \)

If prism \( 1 \) is at minimum deviation condition, then \( \sin i_2 = n_1 \sin\!\left(\frac{A_1}{2}\right) \) always true.