Considering the reaction sequence given below, the correct statement(s) is(are):
P can be reduced to a primary alcohol using \( \mathrm{NaBH_4} \)
Treating P with conc. \( \mathrm{NH_4OH} \) solution followed by acidification gives Q
Treating Q with a solution of \( \mathrm{NaNO_2} \) in aq. \( \mathrm{HCl} \) liberates \( \mathrm{N_2} \)
P is more acidic than \( \mathrm{CH_3CH_2COOH} \)
