Consider a triangle \( PQR \) having sides of lengths \( p,q\) are \(r \) opposite to the angles \( P,Q \) and \( R \), respectively. Then which of the following statements is (are) TRUE?
\( \cos P \ge 1 - \dfrac{p^{2}}{2qr} \)
\( \cos R \ge \left( \dfrac{q-r}{p+q} \right)\cos P + \left( \dfrac{p-r}{p+q} \right)\cos Q \)
\( \dfrac{q+r}{p} < 2\dfrac{\sqrt{\sin Q \sin R}}{\sin P} \)
If \(p<q\) and \(p<r,\) then \(\cos Q > \dfrac{p}{r} \) \( \cos R > \dfrac{p}{q} \)
\(p<q\) and \(p<r,\) then \(\cos Q > \dfrac{p}{r} \) \( \cos R > \dfrac{p}{q} \)