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Chemistry

The reaction sequence(s) that would lead to o-xylene as the major product is(are):

Correct option(s) for the following sequence of reactions is(are):

For the following reaction \( 2X + Y \xrightarrow{k} P \) the rate of reaction is \( \dfrac{d[P]}{dt} = k[X] \). Two moles of \( X \) are mixed with one mole of \( Y \) to make \( 1.0 \,\text{L} \) of solution. At \( 50 \,\text{s} \), \( 0.5 \) mole of \( Y \) is left in the reaction mixture. The correct statement(s) about the reaction is(are):
\( (\text{Use: } \ln 2 = 0.693) \)

23.

Some standard electrode potentials at \( 298 \,\text{K} \) are given below:
\( \text{Pb}^{2+}/\text{Pb} - 0.13 \,\text{V} \)
\( \text{Ni}^{2+}/\text{Ni} - 0.24 \,\text{V} \)
\( \text{Cd}^{2+}/\text{Cd} - 0.40 \,\text{V} \)
\( \text{Fe}^{2+}/\text{Fe} - 0.44 \,\text{V} \)
To a solution containing \( 0.001 \,\text{M} \) of \( X^{2+} \) and \( 0.1 \,\text{M} \) of \( Y^{2+} \), the metal rods \( X \) and \( Y \) are inserted \( (\text{at } 298 \,\text{K}) \) and connected by a conducting wire. This resulted in dissolution of \( X \). The correct combination(s) of \( X \) and \( Y \), respectively, is(are):
\( (\text{Given: Gas constant, } R = 8.314 \,\text{J K}^{-1}\text{mol}^{-1}, \text{ Faraday constant, } F = 96500 \,\text{C mol}^{-1}) \)

24.

The pair(s) of complexes wherein both exhibit tetrahedral geometry is(are):
\( (\text{Note: py = pyridine}) \)
\( \text{Given: Atomic numbers of Fe, Co, Ni and Cu are } 26, 27, 28 \text{ and } 29, \text{ respectively} \)

25.

The correct statement(s) related to oxoacids of phosphorous is(are):

26.

At \( 298 \, \text{K} \), the limiting molar conductivity of a weak monobasic acid is \( 4 \times 10^2 \, \text{S cm}^2 \, \text{mol}^{-1} \). At \( 298 \, \text{K} \), for an aqueous solution of the acid the degree of dissociation is \( \alpha \) and the molar conductivity is \( y \times 10^2 \, \text{S cm}^2 \, \text{mol}^{-1} \). At \( 298 \, \text{K} \), upon \( 20 \) times dilution with water, the molar conductivity of the solution becomes \( 3y \times 10^2 \, \text{S cm}^2 \, \text{mol}^{-1} \).
The value of \( \alpha \) is ____________.

27.

At \( 298 \, \text{K} \), the limiting molar conductivity of a weak monobasic acid is \( 4 \times 10^2 \, \text{S cm}^2 \, \text{mol}^{-1} \). At \( 298 \, \text{K} \), for an aqueous solution of the acid the degree of dissociation is \( \alpha \) and the molar conductivity is \( y \times 10^2 \, \text{S cm}^2 \, \text{mol}^{-1} \). At \( 298 \, \text{K} \), upon \( 20 \) times dilution with water, the molar conductivity of the solution becomes \( 3y \times 10^2 \, \text{S cm}^2 \, \text{mol}^{-1} \).
The value of \( y \) is ____________.

28.

Reaction of \( x \) \( \text{g} \) of \( \text{Sn} \) with \( \text{HCl} \) quantitatively produced a salt. Entire amount of the salt reacted with \( y \) \( \text{g} \) of nitrobenzene in the presence of required amount of \( \text{HCl} \) to produce \( 1.29 \, \text{g} \) of an organic salt (quantitatively).
(Use Molar masses (in \( \text{g mol}^{-1} \)) of H, C, N, O, Cl and Sn as \( 1 \), \( 12 \), \( 14 \), \( 16 \), \( 35 \) and \( 119 \), respectively)
The value of \( x \) is ____________.

29.

Reaction of \( x \) \( \text{g} \) of \( \text{Sn} \) with \( \text{HCl} \) quantitatively produced a salt. Entire amount of the salt reacted with \( y \) \( \text{g} \) of nitrobenzene in the presence of required amount of \( \text{HCl} \) to produce \( 1.29 \, \text{g} \) of an organic salt (quantitatively).
(Use Molar masses (in \( \text{g mol}^{-1} \)) of H, C, N, O, Cl and Sn as \( 1 \), \( 12 \), \( 14 \), \( 16 \), \( 35 \) and \( 119 \), respectively)
The value of \( y \) is ____________.

30.

A sample (\( 5.6 \, \text{g} \)) containing iron is completely dissolved in cold dilute \( \text{HCl} \) to prepare a \( 250 \, \text{mL} \) of solution. Titration of \( 25.0 \, \text{mL} \) of this solution requires \( 12.5 \, \text{mL} \) of \( 0.03 \, \text{M} \) \( \text{KMnO}_4 \) solution to reach the end point. Number of moles of \( \text{Fe}^{2+} \) present in \( 250 \, \text{mL} \) solution is \( x \times 10^{-2} \) (consider complete dissolution of \( \text{Fecl}_2 \)). The amount of iron present in the sample is \( y\% \) by weight.
(Assume: \( \text{KMnO}_4 \) reacts only with \( \text{Fe}^{2+} \) in the solution
Use: Molar mass of iron as \( 56 \, \text{g mol}^{-1} \))
The value of \( x \) is ____________.

31.

A sample (\( 5.6 \, \text{g} \)) containing iron is completely dissolved in cold dilute HCl to prepare a \( 250 \, \text{mL} \) of solution. Titration of \( 25.0 \, \text{mL} \) of this solution requires \( 12.5 \, \text{mL} \) of \( 0.03 \, \text{M} \) \( \mathrm{KMnO_4} \) solution to reach the end point. Number of moles of \( \mathrm{Fe^{2+}} \) present in \( 250 \, \text{mL} \) solution is \( x \times 10^{-2} \) (consider complete dissolution of \( \mathrm{Fecl_2} \) ). The amount of iron present in the sample is \( y\% \) by weight. (Assume: \( \mathrm{KMnO_4} \) reacts only with \( \mathrm{Fe^{2+}} \) in the solution
Use: Molar mass of iron as \( 56 \, \text{g mol}^{-1} \))
The value of \( y \) is ___________ .

32.

The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s-character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below:

Correct match of the C–H bonds (shown in bold) in Column J with their BDE in column K is:

33.

The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s-character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below:

For the following reaction,
\( \mathrm{CH_4(g) + Cl_2(g) \xrightarrow{light} CH_3Cl(g) + HCl(g)} \)
the correct statement is:

34.

The reaction of \( \mathrm{K_3[Fe(CN)_6]} \) with freshly prepared \( \mathrm{FeSO_4} \) solution produces a dark blue precipitate called Turnbull’s blue. Reaction of \( \mathrm{K_4[Fe(CN)_6]} \) with the \( \mathrm{FeSO_4} \) solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the \( \mathrm{FeSO_4} \) solution with \( \mathrm{NaNO_3} \), followed by a slow addition of concentrated \( \mathrm{H_2SO_4} \) through the side of the test tube produces a brown ring.
Precipitate X is:

35.

The reaction of \( \mathrm{K_3[Fe(CN)_6]} \) with freshly prepared \( \mathrm{FeSO_4} \) solution produces a dark blue precipitate called Turnbull’s blue. Reaction of \( \mathrm{K_4[Fe(CN)_6]} \) with the \( \mathrm{FeSO_4} \) solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the \( \mathrm{FeSO_4} \) solution with \( \mathrm{NaNO_3} \), followed by a slow addition of concentrated \( \mathrm{H_2SO_4} \) through the side of the test tube produces a brown ring.
Among the following, the brown ring is due to the formation of:

36.

One mole of an ideal gas at \( 900 \, \text{K} \), undergoes two reversible processes, I followed by II, as shown below. If the work done by the gas in the two processes are same, the value of \( \ln \dfrac{V_3}{V_2} \) is

(\( U \): internal energy, \( S \): entropy, \( p \): pressure, \( V \): volume, \( R \): gas constant)
(Given: molar heat capacity at constant volume, \( C_{v,m} \) of the gas is \( \dfrac{5}{2} R \) )

37.

Consider a helium (He) atom that absorbs a photon of wavelength \( 330 \, \text{nm} \). The change in the velocity (in \( \text{cm s}^{-1} \)) of He atom after the photon absorption is ____________ .
(Assume: Momentum is conserved when photon is absorbed.)
Use: Planck constant = \( 6.6 \times 10^{-34} \, \text{J s} \), Avogadro number = \( 6 \times 10^{23} \, \text{mol}^{-1} \), Molar mass of He = \( 4 \, \text{g mol}^{-1} \)

38.

Ozonolysis of \( \mathrm{ClO_2} \) produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is __________ .

JEE Advance 2021 Paper- 2

Physics Chemistry Mathematics

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The reaction sequence(s) that would lead to o-xylene as the major product is(are):

JEE MainsJEE AdvanceBITSATJEE Advance | PYQ

JEE Mains JEE Advance BITSAT
JEE Advance | PYQ